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Bug
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Resolution: Unresolved
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None
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1.20.80.23 Preview, 1.20.40.20 Preview, 1.20.30.21 Preview, 1.20.30.20 Preview, 1.20.20.23 Preview, 1.20.20.21 Preview, 1.20.20.20 Preview, 1.19.60.22 Preview, 1.19.60.20 Preview, 1.19.41, 1.20.1 Hotfix, 1.20.10, 1.20.12 Hotfix, 1.20.30.25 Preview, 1.20.30.24 Preview, 1.20.15 Hotfix, 1.20.30, 1.20.31 Hotfix, 1.20.40.23 Preview, 1.20.60.23 Preview, 1.20.60.25 Preview, 1.20.60.24 Preview, 1.20.70.21 Preview, 1.20.51 Hotfix, 1.20.60, 1.20.80, 1.20.81 Hotfix
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None
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Confirmed
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Windows
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587462
Summary:
Grindstone breaks when breaking the support block. A “support block” can be any block (the grindstone placed on any block). Only carpets have such behavior, which is a deliberate function (see MC-17833). I think that the support block cannot be for example a flowers. I expect grindstone should not break when breaking the support block, that is, grindstone will not need the supporting block as in Java.
Steps to reproduce:
- Place any block.
- Place grindstone on it.
- Break the block on which you placed a grindstone.
Observed results:
Grindstone broke after breaking the supporting block.
Expected results:
Since grindstone can be placed on any block, it will not break when the supporting block is broken.
Screenshots:
